16x^2-64x=37

Solution for 16x^2-64x=37 equation:

16x^2-64x=37

We move all terms to the left:

16x^2-64x-(37)=0

a = 16; b = -64; c = -37;
Δ = b2-4ac
Δ = -642-4·16·(-37)
Δ = 6464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6464}=\sqrt{64*101}=\sqrt{64}*\sqrt{101}=8\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8\sqrt{101}}{2*16}=\frac{64-8\sqrt{101}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8\sqrt{101}}{2*16}=\frac{64+8\sqrt{101}}{32}
$